NVAMediumJEE Main 2025 · 7 April, Shift 1Nernst Equation

Chemistry Question from JEE Main 2025 · 7 April, Shift 1

1 Faraday electricity was passed through Cu2+\text{Cu}^{2+} (1.5M1.5 \, \text{M}, 1L1 \, \text{L})/Cu and 0.10.1 Faraday was passed through Ag+\text{Ag}^+ (0.2M0.2 \, \text{M}, 1L1 \, \text{L}) electrolytic cells. After this, the two cells were connected as shown below to make an electrochemical cell. The emf of the cell thus formed at 298K298 \, \text{K} is _____ mV. (Nearest integer)

Electrochemical cell diagram with copper electrode in Cu2+ aqueous solution on left, silver electrode in Ag+ aqueous solution on right, connected by a salt bridge and external circuit with galvanometer.

Given: ECu2+/Cu=0.34VE^\circ_{\text{Cu}^{2+}/\text{Cu}} = 0.34 \, \text{V} EAg+/Ag=0.8VE^\circ_{\text{Ag}^+/ \text{Ag}} = 0.8 \, \text{V} 2.303RTF=0.06V\frac{2.303RT}{F} = 0.06 \, \text{V}

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