NVAMediumJEE Main 2026 · 21 January, Shift 2Nernst Equation

Chemistry Question from JEE Main 2026 · 21 January, Shift 2

MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K298 \, \text{K}.

MX(s) ⇌\rightleftharpoons M^{+}(aq) + X^{-}(aq); Ksp=10−10K_{sp} = 10^{-10}

If the standard reduction potential for M+(aq)+e−→M(s)M^{+}(aq) + e^{-} \rightarrow M(s) is (EM+/M∘)=0.79 V(E^{\circ}_{M^{+}/M}) = 0.79 \, \text{V}, then the value of the standard reduction potential for the metal/metal insoluble salt electrode EX−/MX(s)/M∘E^{\circ}_{X^{-}/MX(s)/M} is _____ mV. (nearest integer)

[Given : 2.303RTF=0.059 V\frac{2.303 RT}{F} = 0.059 \, \text{V}]

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