MCQEasyJEE Main 2025 · 7 April, Shift 1Alternating Current Basics

Physics Question from JEE Main 2025 · 7 April, Shift 1

An AC current is represented as: i=52+10cos(650πt+π6)Ampi = 5\sqrt{2} + 10 \cos\left(650\pi t + \frac{\pi}{6}\right)\, \text{Amp} The RMS value of the current is:

  • A

    50Amp50\, \text{Amp}

  • B

    100Amp100\, \text{Amp}

  • C

    10Amp10\, \text{Amp}

  • D

    52Amp5\sqrt{2}\, \text{Amp}

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