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MCQMediumJEE Main 2025 · 24 January, Shift 1Alternating Current Basics

Physics Question from JEE Main 2025 · 24 January, Shift 1

An alternating current is given by I=IAsin⁡ωt+IBcos⁡ωt.I = I_A \sin \omega t + I_B \cos \omega t. The r.m.s. current will be:

  • A

    IA2+IB2\sqrt{I_A^2 + I_B^2}

  • B

    IA2+IB22\frac{\sqrt{I_A^2 + I_B^2}}{2}

  • C

    IA2+IB22\sqrt{\frac{I_A^2 + I_B^2}{2}}

  • D

    ∣IA+IB∣2\frac{|I_A + I_B|}{\sqrt{2}}

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