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MCQEasyJEE Main 2025 · 7 April, Shift 1Displacement Current

Physics Question from JEE Main 2025 · 7 April, Shift 1

If ϵ0\epsilon_0 denotes the permittivity of free space and ΦE\Phi_E is the flux of the electric field through the area bounded by the closed surface, then the dimension of ϵ0dΦEdt\epsilon_0 \frac{d\Phi_E}{dt} are that of:

  • A

    Electric field

  • B

    Electric potential

  • C

    Electric charge

  • D

    Electric current

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