MCQEasyJEE Main 2024 · 1 February, Shift 2Displacement Current

Physics Question from JEE Main 2024 · 1 February, Shift 2

Match List I with List II: List I A. Bdl=μ0ic+μ0ε0dΦEdt\oint \vec{B} \cdot d\vec{l} = \mu_0 i_c + \mu_0 \varepsilon_0 \frac{d\Phi_E}{dt} B. Edl=dΦBdt\oint \vec{E} \cdot d\vec{l} = -\frac{d\Phi_B}{dt} C. EdA=Qε0\oint \vec{E} \cdot d\vec{A} = \frac{Q}{\varepsilon_0} D. BdA=0\oint \vec{B} \cdot d\vec{A} = 0 List II I. Gauss' law for electricity II. Gauss' law for magnetism III. Faraday's law IV. Ampere–Maxwell law Choose the correct answer from the options given below:

  • A

    A-IV, B-I, C-III, D-II

  • B

    A-II, B-III, C-I, D-IV

  • C

    A-IV, B-III, C-I, D-II

  • D

    A-I, B-II, C-III, D-IV

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