MCQMediumJEE Main 2025 · 7 April, Shift 1Trigonometric Equations

Mathematics Question from JEE Main 2025 · 7 April, Shift 1

If for θ[π3,0]\theta \in \left[ -\frac{\pi}{3}, 0 \right], the points (x,y)=(3tan(θ+π3),2tan(θ+π6))(x, y) = \left( 3 \tan\left( \theta + \frac{\pi}{3} \right), 2 \tan\left( \theta + \frac{\pi}{6} \right) \right) lie on xy+αx+βy+γ=0xy + \alpha x + \beta y + \gamma = 0, then α2+β2+γ2\alpha^2 + \beta^2 + \gamma^2 is equal to:

  • A

    8080

  • B

    7272

  • C

    9696

  • D

    7575

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