MCQMediumJEE Main 2025 · 22 January, Shift 2Trigonometric Equations

Mathematics Question from JEE Main 2025 · 22 January, Shift 2

The sum of all values of θ[0,2π]\theta \in [0, 2\pi] satisfying 2sin2θ=cos2θ2\sin^2\theta = \cos 2\theta and 2cos2θ=3sinθ2\cos^2\theta = 3\sin\theta is:

  • A

    π2\frac{\pi}{2}

  • B

    4π4\pi

  • C

    π\pi

  • D

    5π6\frac{5\pi}{6}

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