Jeeify
MCQEasyJEE Main 2025 · 4 April, Shift 2Crystal Field Theory

Chemistry Question from JEE Main 2025 · 4 April, Shift 2

The correct order of [FeF6]3−[FeF_6]^{3-}, [CoF6]3−[CoF_6]^{3-}, [Ni(CO)4][Ni(CO)_4] and [Ni(CN)4]2−[Ni(CN)_4]^{2-} complex species based on the number of unpaired electrons present is:

  • A

    [FeF6]3−>[CoF6]3−>[Ni(CN)4]2−>[Ni(CO)4][FeF_6]^{3-} > [CoF_6]^{3-} > [Ni(CN)_4]^{2-} > [Ni(CO)_4]

  • B

    [Ni(CN)4]2−>[FeF6]3−>[CoF6]3−>[Ni(CO)4][Ni(CN)_4]^{2-} > [FeF_6]^{3-} > [CoF_6]^{3-} > [Ni(CO)_4]

  • C

    [CoF6]3−>[FeF6]3−>[Ni(CO)4]>[Ni(CN)4]2−[CoF_6]^{3-} > [FeF_6]^{3-} > [Ni(CO)_4] > [Ni(CN)_4]^{2-}

  • D

    [FeF6]3−>[CoF6]3−>[Ni(CN)4]2−=[Ni(CO)4][FeF_6]^{3-} > [CoF_6]^{3-} > [Ni(CN)_4]^{2-} = [Ni(CO)_4]

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Sign in to see the solution

Practice more Crystal Field Theory questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Start free trialMore on Crystal Field Theory

Related questions