MCQMediumJEE 2026Crystal Field Theory

JEE Chemistry 2026 Question with Solution

Given below are two statements:

Statement I: Among [Cu(NH3)4]2+[Cu(NH_3)_4]^{2+}, [Ni(en)3]2+[Ni(en)_3]^{2+}, [Ni(NH3)6]2+[Ni(NH_3)_6]^{2+} and [Mn(H2O)6]2+[Mn(H_2O)_6]^{2+}, [Mn(H2O)6]2+[Mn(H_2O)_6]^{2+} has the maximum number of unpaired electrons.

Statement II: The number of pairs among {[NiCl4]2,[Ni(CO)4]}\{[NiCl_4]^{2-}, [Ni(CO)_4]\}, {[NiCl4]2,[Ni(CN)4]2}\{[NiCl_4]^{2-}, [Ni(CN)_4]^{2-}\} and {[Ni(CO)4],[Ni(CN)4]2}\{[Ni(CO)_4], [Ni(CN)_4]^{2-}\} that contain only diamagnetic species is two.

In the light of the above statements, choose the correct answer from the options given below:

  • A

    Statement I is false but Statement II is true

  • B

    Statement I is true but Statement II is false

  • C

    Both Statement I and Statement II are true

  • D

    Both Statement I and Statement II are false

Answer

Correct answer:B

Step-by-step solution

Standard Method

Given: Two statements about magnetic properties of coordination compounds must be checked.

Find: Which option correctly identifies the truth values of Statement I and Statement II.

For each complex, determine the oxidation state, write the dd-electron configuration, use ligand strength and geometry, and then count unpaired electrons.

Statement I

  • [Cu(NH3)4]2+[Cu(NH_3)_4]^{2+}: Copper is +2+2, so Cu2+=3d9Cu^{2+} = 3d^9. A d9d^9 system has 1 unpaired electron.
  • [Ni(en)3]2+[Ni(en)_3]^{2+}: Nickel is +2+2, so Ni2+=3d8Ni^{2+} = 3d^8. Octahedral complex with configuration t2g6eg2t_{2g}^6 e_g^2, so it has 2 unpaired electrons.
  • [Ni(NH3)6]2+[Ni(NH_3)_6]^{2+}: Nickel is +2+2, so Ni2+=3d8Ni^{2+} = 3d^8. Octahedral complex with configuration t2g6eg2t_{2g}^6 e_g^2, so it also has 2 unpaired electrons.
  • [Mn(H2O)6]2+[Mn(H_2O)_6]^{2+}: Manganese is +2+2, so Mn2+=3d5Mn^{2+} = 3d^5. With weak-field H2OH_2O in an octahedral high-spin complex, configuration is t2g3eg2t_{2g}^3 e_g^2, giving 5 unpaired electrons.

So the numbers of unpaired electrons are 1,2,2,1, 2, 2, and 55 respectively. Therefore, [Mn(H2O)6]2+[Mn(H_2O)_6]^{2+} has the maximum number of unpaired electrons.

Statement I is true.

Statement II

Now examine the species in the given pairs.

  • [NiCl4]2[NiCl_4]^{2-}: Nickel is +2+2, so 3d83d^8. Since ClCl^- is a weak-field ligand, the complex is tetrahedral and has 2 unpaired electrons. Hence it is paramagnetic.
  • [Ni(CO)4][Ni(CO)_4]: Nickel is in oxidation state 00. With strong-field COCO, the metal attains paired electrons and the complex is diamagnetic.
  • [Ni(CN)4]2[Ni(CN)_4]^{2-}: Nickel is +2+2, so 3d83d^8. Since CNCN^- is a strong-field ligand, the complex is square planar and diamagnetic.

Check the pairs:

  1. {[NiCl4]2,[Ni(CO)4]}\{[NiCl_4]^{2-}, [Ni(CO)_4]\}: one paramagnetic and one diamagnetic, so not only diamagnetic.
  2. {[NiCl4]2,[Ni(CN)4]2}\{[NiCl_4]^{2-}, [Ni(CN)_4]^{2-}\}: one paramagnetic and one diamagnetic, so not only diamagnetic.
  3. {[Ni(CO)4],[Ni(CN)4]2}\{[Ni(CO)_4], [Ni(CN)_4]^{2-}\}: both are diamagnetic.

Thus, the number of pairs containing only diamagnetic species is one, not two.

Statement II is false.

Therefore, Statement I is true but Statement II is false.

The correct option is B.

Common mistakes

  • Assuming that all Ni2+Ni^{2+} complexes have the same magnetic behavior is incorrect. Geometry and ligand strength matter. First identify whether the complex is tetrahedral, octahedral, or square planar, then count unpaired electrons.

  • Treating [NiCl4]2[NiCl_4]^{2-} as diamagnetic is wrong because ClCl^- is a weak-field ligand and the complex is tetrahedral with unpaired electrons. Do not apply square-planar pairing to weak-field tetrahedral complexes.

  • Counting the number of diamagnetic pairs without checking each species separately can lead to error. First classify every complex as paramagnetic or diamagnetic, and only then evaluate the listed pairs.

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