NVAMediumJEE Main 2025 · 4 April, Shift 2Interference (Young's Experiment)

Physics Question from JEE Main 2025 · 4 April, Shift 2

In a Young's double slit experiment, two slits are located 1.5mm1.5 \, \text{mm} apart. The distance of screen from slits is 2m2 \, \text{m} and the wavelength of the source is 400nm400 \, \text{nm}. If the 2020 maxima of the double slit pattern are contained within the centre maximum of the single slit diffraction pattern, then the width of each slit is x×103cmx \times 10^{-3} \, cm, where x-value is:

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Interference (Young's Experiment) questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions