JEE Physics 2025 Question with Solution

Given: A matching problem on thermodynamic processes and their heat relations.

Find: The correct correspondence between List-I and List-II.

From the solution:

1. Isobaric process (A): pressure remains constant, so

$$\Delta Q = \Delta U + P\Delta V$$

Hence (A) \rightarrow (IV).

2. Isochoric process (B): volume remains constant, so work done is zero and

$$\Delta Q = \Delta U$$

Hence (B) \rightarrow (II).

3. Adiabatic process (C): no heat is exchanged, so

$$\Delta Q = 0$$

Hence (C) \rightarrow (III).

4. Isothermal process (D): temperature remains constant, and for the given list the relation is

$$\Delta Q = \Delta W$$

Hence (D) \rightarrow (I).

Therefore, the correct matching is (A)-(IV), (B)-(II), (C)-(III), (D)-(I), so the correct option is C.

Given: The processes are Isobaric, Isochoric, Adiabatic, and Isothermal.

Find: Which equation matches each process.

Use the first law of thermodynamics:

$$\Delta Q = \Delta U + \Delta W$$

For an isobaric process, work done at constant pressure is

$$\Delta W = P\Delta V$$

So,

$$\Delta Q = \Delta U + P\Delta V$$

Thus (A) \rightarrow (IV).

For an isochoric process,

$$\Delta V = 0 \Rightarrow \Delta W = 0$$

Hence,

$$\Delta Q = \Delta U$$

Thus (B) \rightarrow (II).

For an adiabatic process,

$$\Delta Q = 0$$

Thus (C) \rightarrow (III).

For an isothermal process, the provided relation in the list is

$$\Delta Q = \Delta W$$

Thus (D) \rightarrow (I).

So the final arrangement is (A)-(IV), (B)-(II), (C)-(III), (D)-(I). Therefore, the correct option is C.

The second approach text in the source contains a contradictory description for isobaric and isothermal cases, but it still concludes option (3). The detailed stepwise relation above is consistent with the first approach and the final answer.