Mathematics Question from JEE Main 2025 · 4 April, Shift 2

Consider two sets $A$ and $B$, each containing three numbers in A.P. Let the sum and the product of the elements of $A$ be $36$ and $p$, respectively, and the sum and the product of the elements of $B$ be $36$ and $q$, respectively. Let $d$ and $D$ be the common differences of A.P's in $A$ and $B$, respectively, such that $D = d + 3$, $d > 0$. If $\frac{p+q}{p-q} = \frac{19}{5}$, then $p - q$ is equal to: