MCQEasyJEE 2025Orbitals & Shapes

JEE Chemistry 2025 Question with Solution

Which one of the following about an electron occupying the 1s1s orbital in a hydrogen atom is incorrect ? (Bohr's radius is represented by a0\mathrm{a}_{0} )

  • A

    The probability density of finding the electron is maximum at the nucleus

  • B

    The electron can be found at a distance 2a02 \mathrm{a}_{0} from the nucleus

  • C

    The 1s1s orbital is spherically symmetrical

  • D

    The total energy of the electron is maximum when it is at a distance a0\mathrm{a}_{0} from the nucleus

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: Statements about an electron in the 1s1s orbital of a hydrogen atom are given.

Find: The incorrect statement.

The solution evaluates each statement using properties of the hydrogen atom.

  1. The probability density of finding the electron is maximum at the nucleus. For the 1s1s orbital, the wave function is greatest at the nucleus, so this statement is correct.

  2. The electron can be found at a distance 2a02 \mathrm{a}_{0} from the nucleus. Quantum mechanically, there is non-zero probability of finding the electron at distances other than zero, including 2a02 \mathrm{a}_{0}, so this statement is correct.

  3. The 1s1s orbital is spherically symmetrical. Its probability distribution depends only on distance from the nucleus, not direction, so this statement is correct.

  4. The total energy of the electron is maximum when it is at a distance a0\mathrm{a}_{0} from the nucleus. This is incorrect because for a given energy level, the total energy is quantized and does not depend on the electron's position within the orbital.

Therefore, the incorrect statement is option D.

Option-by-option Check

Given: An electron occupies the 1s1s orbital in a hydrogen atom.

Find: Which statement is incorrect.

The key ideas mentioned in the solution are probability density, allowed distance from the nucleus, spherical symmetry, and total energy.

  • Probability density: The probability density is maximum at the nucleus for the 1s1s orbital. So statement A is correct.
  • Distance from nucleus: The electron may be found at 2a02 \mathrm{a}_{0} because the probability at such a distance is not zero. So statement B is correct.
  • Symmetry: The 1s1s orbital is spherically symmetrical. So statement C is correct.
  • Total energy: The total energy for the electron in the 1s1s state is fixed for that state and is not maximum specifically at a0\mathrm{a}_{0}. So statement D is incorrect.

Hence, the correct option is D.

Common mistakes

  • Confusing probability density with radial probability. The 1s1s probability density is maximum at the nucleus, but that does not mean the most probable radius is also at the nucleus. Keep these two ideas separate.

  • Assuming the electron in an orbital behaves like a classical particle moving on a fixed circular path. In quantum mechanics, an orbital gives a probability distribution, so the electron can be found at different distances such as 2a02 \mathrm{a}_{0}.

  • Thinking the electron's total energy changes with position inside the same orbital. For a given hydrogen energy level, the total energy is fixed by the state, not by where the electron is detected.

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