Number of stereoisomers possible for the complexes, and are respectively
(py = pyridine, ox = oxalate)
- A
- B
- C
- D
Number of stereoisomers possible for the complexes, and are respectively
(py = pyridine, ox = oxalate)
Correct answer:C
Standard Method
Given: The complexes are and .
Find: The number of stereoisomers possible for each complex.
For , chromium is coordinated by six ligands, so the complex has octahedral geometry. This is of the type .
For an octahedral complex of the type , two geometrical arrangements are possible:
Hence, has 2 stereoisomers.
For , oxalate is a bidentate ligand, so the complex is again octahedral. The two chloride ligands can be arranged in cis and trans forms.
The trans form is not optically active. The cis form is chiral and gives a pair of enantiomers.
So the total number of stereoisomers is:
Therefore, the numbers of stereoisomers are and respectively. The correct option is C.
Geometrical and Optical Isomer Counting
Given: Stereoisomers include geometrical and optical isomers.
Find: Count all stereoisomers for both complexes.
Hence, total stereoisomers = .
Hence, total stereoisomers =
Therefore, the required pair is , so the correct option is C.
Counting only geometrical isomers for is incorrect. The cis form is optically active, so its two enantiomers must also be counted. Always include both geometrical and optical isomerism when asked for stereoisomers.
Assuming has only one arrangement is wrong. An octahedral complex can exist in both fac and mer forms. Check the standard octahedral isomer patterns before counting.
Treating the trans form of as optically active is incorrect. The trans arrangement has symmetry and is not chiral. Only the cis form gives an optical pair here.
Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step — free to start.