MCQEasyJEE 2025Photoelectric Effect

JEE Physics 2025 Question with Solution

Given below are two statements: one is labelled as Assertion AA and the other is labelled as Reason RR. Assertion AA: In photoelectric effect, on increasing the intensity of incident light the stopping potential increases. Reason RR: Increase in intensity of light increases the rate of photoelectrons emitted, provided the frequency of incident light is greater than threshold frequency.

  • A

    Both A\mathbf{A} and R\mathbf{R} are true but R\mathbf{R} is NOT the correct explanation of A\mathbf{A}

  • B

    A\mathbf{A} is false but R\mathbf{R} is true

  • C

    A\mathbf{A} is true but R\mathbf{R} is false

  • D

    Both A\mathbf{A} and R\mathbf{R} are true and R\mathbf{R} is the correct explanation of A\mathbf{A}

Answer

Correct answer:B

Step-by-step solution

Standard Method

Given: Assertion AA says that in photoelectric effect, increasing the intensity of incident light increases the stopping potential. Reason RR says that increasing intensity increases the rate of photoelectrons emitted, provided the frequency of incident light is greater than the threshold frequency.

Find: Which option correctly evaluates Assertion AA and Reason RR.

The governing relation is

eV0=Kmax=hνϕeV_0 = K_{\text{max}} = h\nu - \phi

Here, the stopping potential V0V_0 depends on the frequency ν\nu of incident light and the work function ϕ\phi, not on the intensity.

So, if the frequency remains unchanged, increasing the intensity does not increase the stopping potential. Therefore, Assertion AA is false.

When intensity increases, the number of incident photons per second increases. If hν>ϕh\nu > \phi, more electrons are emitted per unit time. Thus, the rate of photoelectron emission increases. Therefore, Reason RR is true.

Hence, Assertion AA is false but Reason RR is true. The correct option is B.

Common mistakes

  • Assuming that higher intensity means higher energy of each photoelectron. This is wrong because intensity changes the number of photons incident per second, not the energy per photon. Use frequency to determine stopping potential and kinetic energy.

  • Confusing stopping potential with photoelectric current. This is incorrect because stopping potential is linked to maximum kinetic energy, whereas current depends on the number of emitted electrons. Keep energy-related and rate-related effects separate.

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