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MCQMediumJEE Main 2025 · 4 April, Shift 1Inverse Trigonometric Functions

Mathematics Question from JEE Main 2025 · 4 April, Shift 1

Considering the principal values of the inverse trigonometric functions, sin⁡−1(32x+121−x2)\sin^{-1} \left( \frac{\sqrt{3}}{2} x + \frac{1}{2} \sqrt{1-x^2} \right), −12<x<12-\frac{1}{2} < x < \frac{1}{\sqrt{2}}, is equal to

  • A

    π4+sin⁡−1x\frac{\pi}{4} + \sin^{-1} x

  • B

    π6+sin⁡−1x\frac{\pi}{6} + \sin^{-1} x

  • C

    −5π6−sin⁡−1x\frac{-5\pi}{6} - \sin^{-1} x

  • D

    5π6−sin⁡−1x\frac{5\pi}{6} - \sin^{-1} x

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