NVAMediumJEE Main 2025 · 3 April, Shift 1Probability Distributions

Mathematics Question from JEE Main 2025 · 3 April, Shift 1

All five letter words are made using all the letters A, B, C, D, E and arranged as in an English dictionary with serial numbers. Let the word at serial number nn be denoted by WnW_n. Let the probability P(Wn)P(W_n) of choosing the word WnW_n satisfy P(Wn)=2P(Wn1)P(W_n) = 2P(W_{n-1}), n>1n > 1. If P(CDBEA)=2α2β1P(CDBEA) = \frac{2^\alpha}{2^\beta - 1}, α,βN\alpha, \beta \in \mathbb{N}, then α+β\alpha + \beta is equal to :

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