MCQEasyJEE Main 2026 · 24 January, Shift 1Probability Distributions

Mathematics Question from JEE Main 2026 · 24 January, Shift 1

From a lot containing 1010 defective and 9090 non-defective bulbs, 88 bulbs are selected one by one with replacement. Then the probability of getting at least 77 defective bulbs is

  • A

    67108\dfrac{67}{10^8}

  • B

    73108\dfrac{73}{10^8}

  • C

    7107\dfrac{7}{10^7}

  • D

    81108\dfrac{81}{10^8}

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