MCQMediumJEE Main 2025 · 3 April, Shift 1Simple Applications

Mathematics Question from JEE Main 2025 · 3 April, Shift 1

If r=19(r+32r)9Cr=α(32)9β\sum_{r=1}^{9} \left( \frac{r+3}{2^r} \right) \cdot {^9C_r} = \alpha \left( \frac{3}{2} \right)^9 - \beta, α,βN\alpha, \beta \in \mathbb{N}, then (α+β)2(\alpha + \beta)^2 is equal to

  • A

    2727

  • B

    99

  • C

    8181

  • D

    1818

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