NVAMediumJEE Main 2025 · 22 January, Shift 1Simple Applications

Mathematics Question from JEE Main 2025 · 22 January, Shift 1

If r=0511C2r+12r+2=mn\sum_{r=0}^5 \frac{{}^{11}C_{2r+1}}{2r+2} = \frac{m}{n}, gcd(m,nm, n) = 11, then mnm - n is equal to:

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