MCQEasyJEE 2025Trends in Atomic Radius & Ionisation Energy

JEE Chemistry 2025 Question with Solution

First ionisation enthalpy values of the first four group 1515 elements are given below. Choose the correct value for the element that is a main component of the apatite family:

  • A

    1012kJ mol11012 \, \text{kJ mol}^{-1}

  • B

    1402kJ mol11402 \, \text{kJ mol}^{-1}

  • C

    834kJ mol1834 \, \text{kJ mol}^{-1}

  • D

    947kJ mol1947 \, \text{kJ mol}^{-1}

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given: First ionisation enthalpy values of group 1515 elements are listed in the options.

Find: The correct value for the element that is a main component of the apatite family.

Apatite minerals are mainly phosphate minerals, so the key element involved is phosphorus.

Phosphorus belongs to group 1515, and its first ionisation enthalpy is

1012kJ mol11012 \, \text{kJ mol}^{-1}

Hence, the required value is 1012kJ mol11012 \, \text{kJ mol}^{-1}.

Therefore, the correct option is A.

Step-by-step Identification

Given: We need to identify the first ionisation enthalpy of the element that is the main component of the apatite family.

Find: Which option matches that value.

Apatite is a group of phosphate minerals with general formula

Ca5(PO4)3(F, Cl, OH)\text{Ca}_5(\text{PO}_4)_3(\text{F, Cl, OH})

So, the key element is phosphorus because it occurs in the phosphate ion

PO43\text{PO}_4^{3-}

The first ionisation enthalpy trend down group 1515 decreases approximately as:

  • N=1402kJ mol1\text{N} = 1402 \, \text{kJ mol}^{-1}
  • P=1012kJ mol1\text{P} = 1012 \, \text{kJ mol}^{-1}
  • As=947kJ mol1\text{As} = 947 \, \text{kJ mol}^{-1}
  • Sb=834kJ mol1\text{Sb} = 834 \, \text{kJ mol}^{-1}

Thus, for phosphorus, the correct value is 1012kJ mol11012 \, \text{kJ mol}^{-1}.

Therefore, the correct option is A.

Common mistakes

  • Confusing apatite with a nitrogen-containing mineral is incorrect because apatite belongs to the phosphate mineral family. Identify the relevant element from the phosphate ion first, which points to phosphorus.

  • Choosing the highest ionisation enthalpy by trend alone is incorrect because the question asks for a specific element, not the general trend winner. First identify the element in apatite, then match its value.

  • Mixing up the group 1515 values for phosphorus, arsenic, and antimony is a common error. After identifying phosphorus, select 1012kJ mol11012 \, \text{kJ mol}^{-1}, not the nearby values 947947 or 834834.

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