JEE Chemistry 2025 Question with Solution

Given: We need to match List - I saccharides with List - II glycosidic linkages.

Find: The correct option containing the correct matching.

From the solution working:

• Sucrose has linkage $\alpha 1-\beta 2$.
• Maltose has linkage $\alpha 1-4$.
• Lactose has linkage $\beta 1-4$.
• Amylopectin has linkages $\alpha 1-4$ and $\alpha 1-6$.

Therefore the correct matching is:

• $(A)-(III)$
• $(B)-(I)$
• $(C)-(IV)$
• $(D)-(II)$

This matching corresponds to Option C in the given options.

The solution states this matching explicitly, although one approach incorrectly formats the final answer as Option B. Based on the actual linkage matching shown in the solution, the defensible correct option is C.

Given:

• Sucrose
• Maltose
• Lactose
• Amylopectin

Find: Match each with its glycosidic linkage.

1. Sucrose is formed by glucose and fructose through $\alpha 1-\beta 2$ linkage, so $A \to III$.
2. Maltose contains two glucose units connected by $\alpha 1-4$ linkage, so $B \to I$.
3. Lactose contains galactose and glucose connected by $\beta 1-4$ linkage, so $C \to IV$.
4. Amylopectin is branched and contains both $\alpha 1-4$ and $\alpha 1-6$ linkages, so $D \to II$.

Hence the full matching is $(A)-(III), (B)-(I), (C)-(IV), (D)-(II)$.

Comparing with the options, this is Option C.

Therefore, the correct option is C.