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MCQEasyJEE 2026Carbohydrates (Glucose, Fructose, Sucrose…)

JEE Chemistry 2026 Question with Solution

Given below are two statements:

Statement I: Sucrose is dextrorotatory. However, sucrose upon hydrolysis gives a solution having mixture of products. This solution shows laevorotation.

Statement II: Hydrolysis of sucrose gives glucose and fructose. Since the laevorotation of fructose is more than the dextrorotation of glucose, the resulting solution becomes laevorotatory.

In the light of the above statements, choose the correct answer from the options given below.

  • A

    Statement I is false but Statement II is true

  • B

    Statement I is true but Statement II is false

  • C

    Both Statement I and Statement II are false

  • D

    Both Statement I and Statement II are true

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: Two statements about the optical activity of sucrose and its hydrolysis products.

Find: Which option correctly evaluates Statement I and Statement II.

Step 1: Analysis of Statement I

Sucrose is dextrorotatory in nature. On hydrolysis, sucrose breaks down into equimolar amounts of glucose and fructose, forming invert sugar. The resulting solution shows laevorotation. Hence, Statement I is correct.

Step 2: Analysis of Statement II

Glucose is dextrorotatory, whereas fructose is strongly laevorotatory. The magnitude of laevorotation of fructose is greater than the dextrorotation of glucose. Therefore, the net rotation of the mixture becomes laevorotatory. Hence, Statement II is also correct.

Step 3: Final conclusion

Both Statement I and Statement II are true.

Therefore, the correct option is D.

Common mistakes

  • Confusing which sugar is more strongly optically active. The mixture after hydrolysis becomes laevorotatory because fructose has a greater laevorotation magnitude than the dextrorotation of glucose. Compare the magnitudes of rotation, not just their signs.

  • Assuming hydrolysis preserves the optical nature of sucrose. This is incorrect because hydrolysis forms a new mixture of glucose and fructose, so the net optical rotation changes. Always judge the products after reaction, not the reactant alone.

  • Believing Statement II is false because glucose is dextrorotatory. The final rotation depends on the combined effect of both products, and the stronger laevorotation of fructose dominates. Consider net rotation of the mixture.

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