MCQEasyJEE 2025Crystal Field Theory

JEE Chemistry 2025 Question with Solution

The metal ion whose electronic configuration is not affected by the nature of the ligand and which gives a violet color in non-luminous flame under hot condition in borax bead test is:

  • A

    Ti3+\mathrm{Ti}^{3+}

  • B

    Cr3+\mathrm{Cr}^{3+}

  • C

    Ni2+\mathrm{Ni}^{2+}

  • D

    Mn2+\mathrm{Mn}^{2+}

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: We need the metal ion whose electronic configuration is not affected by the nature of the ligand and which gives a violet color in the borax bead test under hot condition.

Find: The correct option.

A metal ion whose electronic configuration remains essentially unaffected by ligand field considerations is expected to have a specially stable configuration such as a half-filled d-subshell. Among the given ions, Mn2+\mathrm{Mn}^{2+} has configuration 3d53d^5, which is half-filled and particularly stable.

From the borax bead test colors given in the solution:

  • Cr3+\mathrm{Cr}^{3+} gives green when hot.
  • Ni2+\mathrm{Ni}^{2+} gives reddish brown.
  • Mn2+\mathrm{Mn}^{2+} gives violet when hot.

Therefore, the ion satisfying both conditions is Mn2+\mathrm{Mn}^{2+}.

The correct option is D.

Using ligand-field stability and borax bead color

Given: The required ion must satisfy two conditions:

  1. Its electronic configuration is not affected by the nature of the ligand.
  2. It gives a violet color in the hot borax bead test.

Find: Which option matches both conditions.

Step 1: Check electronic configuration stability. A half-filled or fully filled d-subshell is especially stable and is least affected in this context by the ligand nature.

Among the options:

  • Ti3+:d1\mathrm{Ti}^{3+} : d^1
  • Cr3+:d3\mathrm{Cr}^{3+} : d^3
  • Ni2+:d8\mathrm{Ni}^{2+} : d^8
  • Mn2+:d5\mathrm{Mn}^{2+} : d^5

Step 2: Identify the ion with the most stable configuration. Mn2+\mathrm{Mn}^{2+} has the half-filled configuration d5d^5, so it matches the first condition.

Step 3: Use the borax bead test color. The violet-colored bead in hot condition is produced by Mn2+\mathrm{Mn}^{2+}.

Conclusion: Both criteria point to Mn2+\mathrm{Mn}^{2+}. Hence, the final answer is Option D.

Common mistakes

  • Choosing Cr3+\mathrm{Cr}^{3+} because the answer key key says option B. This is wrong because the extracted solution working repeatedly concludes that the violet hot borax bead color corresponds to Mn2+\mathrm{Mn}^{2+}. Use the solution working.

  • Focusing only on electronic configuration and ignoring the borax bead color. Even if a stable d-configuration is identified, the color condition must also be checked; the violet hot bead points to Mn2+\mathrm{Mn}^{2+}.

  • Confusing hot and cold bead colors in the borax bead test. The question asks for violet color under hot condition, so the color must be matched specifically for the hot bead, not after cooling.

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