MCQEasyJEE Main 2025 · 28 January, Shift 1Second Law & Heat Engines

Physics Question from JEE Main 2025 · 28 January, Shift 1

A Carnot engine (E) is working between two temperatures 473K473\,\text{K} and 273K273\,\text{K}. In a new system two engines - engine E1E_1 works between 473K473\,\text{K} to 373K373\,\text{K} and engine E2E_2 works between 373K373\,\text{K} to 273K273\,\text{K}. If η12\eta_{12}, η1\eta_1 and η2\eta_2 are the efficiencies of the engines EE, E1E_1 and E2E_2, respectively, then:

  • A

    η12<η1+η2\eta_{12} < \eta_1 + \eta_2

  • B

    η12=η1+η2\eta_{12} = \eta_1 + \eta_2

  • C

    η12=η1η2\eta_{12} = \eta_1 \eta_2

  • D

    η12>η1+η2\eta_{12} > \eta_1 + \eta_2

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