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MCQMediumJEE Main 2025 · 24 January, Shift 2Nernst Equation

Chemistry Question from JEE Main 2025 · 24 January, Shift 2

Based on the data given below: ECr2O72−/Cr3+∘=1.33 V,ECl2/Cl−∘=1.36 V,EMnO4−/Mn2+∘=1.51 V,ECr3+/Cr∘=−0.74 V.E^\circ_{Cr_2O_7^{2-}/Cr^{3+}} = 1.33 \, V, \quad E^\circ_{Cl_2/Cl^-} = 1.36 \, V, \quad E^\circ_{MnO_4^-/Mn^{2+}} = 1.51 \, V, \quad E^\circ_{Cr^{3+}/Cr} = -0.74 \, V. The strongest reducing agent is:

  • A

    Mn2+Mn^{2+}

  • B

    MnO4−MnO_4^-

  • C

    CrCr

  • D

    Cl−Cl^-

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