NVAMediumJEE Main 2025 · 24 January, Shift 1Equilibrium Basics

Chemistry Question from JEE Main 2025 · 24 January, Shift 1

37.8 g37.8 \, \text{g} N2O5N_2O_5 was taken in a 1 L1 \, \text{L} reaction vessel and allowed to undergo the following reaction at 500 K500 \, \text{K}:

2N2O5(g)→2N2O4(g)+O2(g)2N_2O_5(g) \rightarrow 2N_2O_4(g) + O_2(g)

The total pressure at equilibrium was found to be 18.65 bar18.65 \, \text{bar}. Then, KpK_p is _____ ×10−2\times 10^{-2} (nearest integer). Assume N2O5N_2O_5 behaves ideally under these conditions. Given:

R=0.082 bar L mol−1K−1R = 0.082 \, \text{bar L mol}^{-1} \text{K}^{-1}

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