MCQMediumJEE Main 2026 · 24 January, Shift 2Equilibrium Basics

Chemistry Question from JEE Main 2026 · 24 January, Shift 2

Consider the following gaseous equilibrium in a closed container of volume VV at temperature TT:

P2(g)+Q2(g)2PQ(g)P_2(\text{g}) + Q_2(\text{g}) \rightleftharpoons 2PQ(\text{g})

Initially, 22 moles each of P2(g)P_2(\text{g}), Q2(g)Q_2(\text{g}) and PQ(g)PQ(\text{g}) are present at equilibrium. One mole each of P2P_2 and Q2Q_2 are added. The number of moles of P2P_2, Q2Q_2 and PQPQ at the new equilibrium respectively are

  • A

    1.211.21, 2.242.24, 1.561.56

  • B

    2.672.67, 2.672.67, 2.672.67

  • C

    1.661.66, 1.661.66, 1.661.66

  • D

    2.562.56, 1.621.62, 2.242.24

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