MCQMediumJEE Main 2025 · 24 January, Shift 1Torque & Angular Momentum

Physics Question from JEE Main 2025 · 24 January, Shift 1

An object of mass mm is projected from the origin in a vertical xyxy-plane at an angle 4545^\circ with the x-axis with an initial velocity v0v_0. The magnitude and direction of the angular momentum of the object with respect to the origin, when it reaches the maximum height, will be [gg is the acceleration due to gravity]:

  • A

    mv0322g\frac{mv_0^3}{2\sqrt{2}g} along negative z-axis

  • B

    mv0322g\frac{mv_0^3}{2\sqrt{2}g} along positive z-axis

  • C

    mv0342g\frac{mv_0^3}{4\sqrt{2}g} along positive z-axis

  • D

    mv0342g\frac{mv_0^3}{4\sqrt{2}g} along negative z-axis

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