MCQEasyJEE 2025Torque & Angular Momentum

JEE Physics 2025 Question with Solution

Which of the following are correct expression for torque acting on a body?

A. τ¨=r¨×L¨\ddot{\tau}=\ddot{\mathrm{r}} \times \ddot{\mathrm{L}}

B. τ¨=ddt(r¨×p¨)\ddot{\tau}=\frac{\mathrm{d}}{\mathrm{dt}}(\ddot{\mathrm{r}} \times \ddot{\mathrm{p}})

C. τ¨=r¨×dp˙dt\ddot{\tau}=\ddot{\mathrm{r}} \times \frac{\mathrm{d} \dot{\mathrm{p}}}{\mathrm{dt}}

D. τ¨=Iα˙\ddot{\tau}=\mathrm{I} \dot{\alpha}

E. τ¨=r¨×F¨\ddot{\tau}=\ddot{\mathrm{r}} \times \ddot{\mathrm{F}}

(r¨=\ddot{r}= position vector; p˙=\dot{\mathrm{p}}= linear momentum; L¨=\ddot{\mathrm{L}}= angular momentum; α¨=\ddot{\alpha}= angular acceleration; I=\mathrm{I}= moment of inertia; F¨=\ddot{\mathrm{F}}= force; t=\mathrm{t}= time)

Choose the correct answer from the options given below:

  • A

    B, D and E Only

  • B

    C and D Only

  • C

    B, C, D and E Only

  • D

    A, B, D and E Only

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: We must identify which listed expressions are valid forms of torque acting on a body.

Find: The correct option containing all valid expressions for torque.

Torque can be written in equivalent forms as

τ=dLdt=r×F\vec{\tau} = \frac{d\vec{L}}{dt} = \vec{r} \times \vec{F}

Also, using rotational dynamics for a rigid body about a fixed axis,

τ=Iα\vec{\tau} = I\vec{\alpha}

Since

L=r×p\vec{L} = \vec{r} \times \vec{p}

we get

τ=dLdt=ddt(r×p)\vec{\tau} = \frac{d\vec{L}}{dt} = \frac{d}{dt}(\vec{r} \times \vec{p})

And because

F=dpdt\vec{F} = \frac{d\vec{p}}{dt}

we also have

τ=r×dpdt=r×F\vec{\tau} = \vec{r} \times \frac{d\vec{p}}{dt} = \vec{r} \times \vec{F}

Now check each statement:

  • A is incorrect because torque is not r×L\vec{r} \times \vec{L}.
  • B is correct because L=r×p\vec{L} = \vec{r} \times \vec{p}.
  • C is correct because dpdt=F\frac{d\vec{p}}{dt} = \vec{F}.
  • D is correct for rigid body rotation about a fixed axis.
  • E is correct because torque is r×F\vec{r} \times \vec{F}.

Therefore, the correct expressions are B, C, D and E only.

The correct option is C.

Option-wise Verification

Given: The listed expressions relate torque with position vector, momentum, angular momentum, force, and angular acceleration.

Find: Which of the statements A to E are valid.

Step 1: Test statement A.

τr×L\vec{\tau} \ne \vec{r} \times \vec{L}

Torque is the time derivative of angular momentum, not the cross product of position vector with angular momentum. So A is incorrect.

Step 2: Test statement B. Using

L=r×p\vec{L} = \vec{r} \times \vec{p}

Differentiate with respect to time:

τ=dLdt=ddt(r×p)\vec{\tau} = \frac{d\vec{L}}{dt} = \frac{d}{dt}(\vec{r} \times \vec{p})

So B is correct.

Step 3: Test statement C. Since

dpdt=F\frac{d\vec{p}}{dt} = \vec{F}

we get

τ=r×dpdt=r×F\vec{\tau} = \vec{r} \times \frac{d\vec{p}}{dt} = \vec{r} \times \vec{F}

So C is correct.

Step 4: Test statement D. For rotational motion of a rigid body about a fixed axis,

τ=Iα\vec{\tau} = I\vec{\alpha}

Hence D is correct.

Step 5: Test statement E. The fundamental definition of torque is

τ=r×F\vec{\tau} = \vec{r} \times \vec{F}

Hence E is correct.

Thus the correct set is B, C, D and E only, which matches option C.

Common mistakes

  • Confusing torque with r×L\vec{r} \times \vec{L}. This is wrong because torque is the time derivative of angular momentum, not its cross product with position vector. Use τ=dLdt\vec{\tau} = \frac{d\vec{L}}{dt} instead.

  • Assuming τ=Iα\vec{\tau} = I\vec{\alpha} is the only definition of torque. This is incomplete because it is a special rotational-dynamics form, typically for rigid body rotation about a fixed axis. The fundamental relation is τ=r×F\vec{\tau} = \vec{r} \times \vec{F}.

  • Forgetting that F=dpdt\vec{F} = \frac{d\vec{p}}{dt}. Without this relation, students may fail to see why r×dpdt\vec{r} \times \frac{d\vec{p}}{dt} is a valid torque expression. First replace dpdt\frac{d\vec{p}}{dt} by force, then compare with the standard definition.

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