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MCQMediumJEE Main 2025 · 23 January, Shift 2Equation of Line in 3D

Mathematics Question from JEE Main 2025 · 23 January, Shift 2

The distance of the line x−22=y−63=z−34\frac{x - 2}{2} = \frac{y - 6}{3} = \frac{z - 3}{4} from the point (1,4,0)(1, 4, 0) along the line x1=y−22=z+33\frac{x}{1} = \frac{y - 2}{2} = \frac{z + 3}{3} is:

  • A

    17\sqrt{17}

  • B

    14\sqrt{14}

  • C

    15\sqrt{15}

  • D

    13\sqrt{13}

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