JEE Chemistry 2025 Question with Solution

Given: A matching problem on thermodynamic processes.

Find: The correct correspondence between the statements in List-I and the processes in List-II.

From the extracted solution table:

• A. Pressure varies inversely with volume of an ideal gas $\rightarrow$ III. Isothermal process
• B. Heat absorbed goes partly to increase internal energy and partly to do work $\rightarrow$ IV. Isobaric process
• C. Heat is neither absorbed nor released by a system $\rightarrow$ I. Adiabatic process
• D. No work is done on or by a gas $\rightarrow$ II. Isochoric process

Use the basic thermodynamic definitions:

1. In an isothermal process, temperature remains constant, so for an ideal gas,

$$PV = \text{constant}$$

Hence pressure varies inversely with volume. Therefore A $\rightarrow$ III.

2. In an isobaric process, pressure remains constant and the heat supplied is used partly to increase internal energy and partly to do work. Therefore B $\rightarrow$ IV.

3. In an adiabatic process, no heat is exchanged with the surroundings, so

$$Q = 0$$

Therefore C $\rightarrow$ I.

4. In an isochoric process, volume remains constant, so work done is

$$W = \int P \, dV = 0$$

Therefore D $\rightarrow$ II.

Thus the correct matching is:

• A $\rightarrow$ III
• B $\rightarrow$ IV
• C $\rightarrow$ I
• D $\rightarrow$ II

the solution explicitly states The Correct Option is D. However, this mapping does not match any option verbatim. Among the given options, Option D is marked correct on the solution, so the answer is taken as D with this discrepancy noted.

Given: Descriptions of four thermodynamic situations.

Find: Which process name matches each description.

• If pressure varies inversely with volume for an ideal gas, Boyle's law applies at constant temperature, so the process is isothermal.
• If absorbed heat is split between increasing internal energy and doing work, the process is isobaric.
• If no heat is absorbed or released, the process is adiabatic.
• If no work is done, then volume does not change, so the process is isochoric because

$$W = \int P \, dV = 0$$

when $dV = 0$.

So the matching is A-III, B-IV, C-I, D-II.

The source solution still declares Option D as correct, and by the answer-resolution rule the solution is treated. Therefore, the recorded answer is D, while the textual matching from the same solution indicates a mismatch with the listed options.