MCQEasyJEE 2025Isothermal & Adiabatic Processes

JEE Physics 2025 Question with Solution

Match the LIST-I with LIST-II

A matching table for thermodynamics processes in LIST-I and LIST-II, asking to match process descriptions with named thermodynamic processes.
  • A

    A-II, B-III, C-I, D-IV

  • B

    A-IV, B-I, C-III, D-II

  • C

    A-IV, B-III, C-I, D-II

  • D

    A-II, B-I, C-III, D-IV

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: A matching problem on thermodynamic processes.

Find: The correct correspondence between the statements in LIST-I and the processes in LIST-II.

From the solution content:

  • A. Pressure varies inversely with volume of an ideal gas \rightarrow Isothermal process
  • B. Heat absorbed goes partly to increase internal energy and partly to do work \rightarrow Isobaric process
  • C. Heat is neither absorbed nor released by a system \rightarrow Adiabatic process
  • D. No work is done on or by a gas \rightarrow Isochoric process

Use the thermodynamic definitions:

  1. For an isothermal process of an ideal gas,
PV=constantPV = \text{constant}

so pressure varies inversely with volume. Hence A \rightarrow III.

  1. In an isobaric process, heat supplied is used partly to increase internal energy and partly to do work. Hence B \rightarrow IV.

  2. In an adiabatic process,

Q=0Q = 0

so no heat is absorbed or released. Hence C \rightarrow I.

  1. In an isochoric process,
W=PdV=0W = \int P \, dV = 0

because volume remains constant. Hence D \rightarrow II.

Therefore, the correct match is A-III, B-IV, C-I, D-II.

This exact combination is not listed verbatim in the options. The closest defensible listed option from the provided choices is A-IV, B-III, C-I, D-II, which is Option C on the page, but the extracted solution working concludes A-III, B-IV, C-I, D-II. This indicates a discrepancy between the listed options and the solution text.

Therefore, based on the provided answer key mapping, the marked correct option is C.

Concept-wise Matching

Given: Statements describing thermodynamic behaviour.

Find: Which named process corresponds to each statement.

  • A. Pressure varies inversely with volume of an ideal gas For an ideal gas at constant temperature,
PV=constantPV = \text{constant}

This is the defining relation of an isothermal process. So A \rightarrow III.

  • B. Heat absorbed goes partly to increase internal energy and partly to do work This is the standard description of an isobaric process, where supplied heat is split between internal energy increase and work done. So B \rightarrow IV.

  • C. Heat is neither absorbed nor released by a system That means

Q=0Q = 0

which defines an adiabatic process. So C \rightarrow I.

  • D. No work is done on or by a gas Work done by a gas is
W=PdVW = \int P \, dV

If volume does not change, then dV=0dV = 0 and hence W=0W = 0. This is an isochoric process. So D \rightarrow II.

Thus the final matching is:

  • A \rightarrow III
  • B \rightarrow IV
  • C \rightarrow I
  • D \rightarrow II

Hence the correct matching written in full is A-III, B-IV, C-I, D-II.

Common mistakes

  • Confusing isothermal with isobaric. In an isothermal process, temperature remains constant and for an ideal gas PV=constantPV = \text{constant}, so pressure varies inversely with volume. Constant pressure is the condition for an isobaric process, not isothermal.

  • Thinking that 'heat absorbed goes partly into internal energy and partly into work' describes an adiabatic process. This is wrong because in an adiabatic process Q=0Q = 0. That statement fits an isobaric process where heat supplied is distributed between ΔU\Delta U and WW.

  • Missing that no work is done when volume does not change. Since W=PdVW = \int P \, dV, if dV=0dV = 0 throughout the process, then work is zero. Therefore this corresponds to an isochoric process, not an adiabatic one.

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