MCQMediumJEE Main 2025 · 23 January, Shift 1Refraction & Lenses

Physics Question from JEE Main 2025 · 23 January, Shift 1

Given a thin convex lens (refractive index μ2\mu_2), kept in a liquid (refractive index μ1,μ1<μ2\mu_1, \mu_1 < \mu_2) having radii of curvature ∣R1∣|R_1| and ∣R2∣|R_2|. Its second surface is silver polished. Where should an object be placed on the optic axis so that a real and inverted image is formed at the same place?

  • A

    μ1∣R1∣∣R2∣μ2(∣R1∣+∣R2∣)−μ1∣R1∣\frac{\mu_1 |R_1| |R_2|}{\mu_2 (|R_1| + |R_2|) - \mu_1 |R_1|}

  • B

    μ1∣R1∣∣R2∣μ2(∣R1∣+∣R2∣)−μ1∣R2∣\frac{\mu_1 |R_1| |R_2|}{\mu_2 (|R_1| + |R_2|) - \mu_1 |R_2|}

  • C

    μ1∣R1∣∣R2∣μ2(2∣R1∣+∣R2∣)−μ1∣R1∣∣R2∣\frac{\mu_1 |R_1| |R_2|}{\mu_2 (2|R_1| + |R_2|) - \mu_1 \sqrt{|R_1| |R_2|}}

  • D

    (μ2+μ1)∣R1∣μ2−μ1\frac{(\mu_2 + \mu_1) |R_1|}{\mu_2 - \mu_1}

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