Given a thin convex lens (refractive index μ₂), kept in a liquid (refractive index μ₁, μ₁

Question

Given a thin convex lens (refractive index $$\mu_2$$), kept in a liquid (refractive index $$\mu_1, \mu_1 < \mu_2$$) having radii of curvature $$|R_1|$$ and $$|R_2|$$. Its second surface is silver polished. Where should an object be placed on the optic axis so that a real and inverted image is formed at the same place?

Accepted Answer

B. $$\frac{\mu_1 |R_1| |R_2|}{\mu_2 (|R_1| + |R_2|) - \mu_1 |R_2|}$$

Answer

A. $$\frac{\mu_1 |R_1| |R_2|}{\mu_2 (|R_1| + |R_2|) - \mu_1 |R_1|}$$

Answer

C. $$\frac{\mu_1 |R_1| |R_2|}{\mu_2 (2|R_1| + |R_2|) - \mu_1 \sqrt{|R_1| |R_2|}}$$

Answer

D. $$\frac{(\mu_2 + \mu_1) |R_1|}{\mu_2 - \mu_1}$$

Answer & step-by-step solution

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