MCQEasyJEE 2025Isothermal & Adiabatic Processes

JEE Physics 2025 Question with Solution

Match the List-I with List-II

A matching table with List-I statements A to D about thermodynamic processes and List-II entries I Adiabatic process, II Isochoric process, III Isothermal process, IV Isobaric process.

Choose the correct answer from the options given below:

  • A

    A–I, B–IV, C–II, D–III

  • B

    A–III, B–I, C–IV, D–II

  • C

    A–I, B–III, C–II, D–IV

  • D

    A–III, B–IV, C–I, D–II

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: A matching problem on thermodynamic processes.

Find: The correct correspondence between List-I and List-II.

From the solution table:

  • A. Pressure varies inversely with volume of an ideal gas.
  • B. Heat absorbed goes partly to increase internal energy and partly to do work.
  • C. Heat is neither absorbed nor released by a system.
  • D. No work is done on or by a gas.

Now match each statement:

  1. A corresponds to the isothermal process because for an ideal gas at constant temperature,
PV=constantPV = \text{constant}

so pressure varies inversely with volume. Therefore, A \to III.

  1. B corresponds to the isobaric process. In a constant-pressure process, absorbed heat is used partly to increase internal energy and partly to do work. Therefore, B \to IV.

  2. C corresponds to the adiabatic process because no heat is exchanged with the surroundings, that is,

Q=0Q = 0

Therefore, C \to I.

  1. D corresponds to the isochoric process. At constant volume,
W=PdV=0W = \int P \, dV = 0

because dV=0dV = 0. Therefore, D \to II.

Hence, the correct matching is A–III, B–IV, C–I, D–II.

Therefore, the correct option is D.

Direct Identification

Given: Statements describing four thermodynamic processes.

Find: The correct match.

Use the defining property of each process directly:

  • In an isothermal process, for an ideal gas, pressure varies inversely with volume, so A \to III.
  • In an isobaric process, heat supplied changes internal energy and also does work, so B \to IV.
  • In an adiabatic process, no heat is absorbed or released, so C \to I.
  • In an isochoric process, volume remains constant and no work is done, so D \to II.

Thus the match is A–III, B–IV, C–I, D–II, so the correct option is D.

Common mistakes

  • Confusing isothermal with adiabatic. Pressure varying inversely with volume for an ideal gas follows from PV=constantPV = \text{constant} at constant temperature, so it indicates an isothermal process, not an adiabatic one.

  • Assuming no heat exchange means no internal energy change. In an adiabatic process, Q=0Q = 0, but internal energy can still change because work may be done by or on the gas.

  • Mixing up isochoric and isobaric processes. No work is done in an isochoric process because volume is constant and dV=0dV = 0. In an isobaric process, pressure is constant, but work can still be non-zero.

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