MCQMediumJEE Main 2025 · 22 January, Shift 2Equation of Line in 3D

Mathematics Question from JEE Main 2025 · 22 January, Shift 2

The perpendicular distance of the line x12=y+21=z+32\frac{x - 1}{2} = \frac{y + 2}{-1} = \frac{z + 3}{2} from the point P(2,10,1)P(2, -10, 1) is:

  • A

    434\sqrt{3}

  • B

    525\sqrt{2}

  • C

    353\sqrt{5}

  • D

    66

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