MCQEasyJEE 2025Faraday's Laws of Electrolysis

JEE Chemistry 2025 Question with Solution

Which of the following electrolyte can be used to obtain H2S2O8\text{H}_2\text{S}_2\text{O}_8 by the process of electrolysis?

  • A

    Dilute solution of sodium sulphate

  • B

    Dilute solution of sulphuric acid

  • C

    Concentrated solution of sulphuric acid

  • D

    Acidified dilute solution of sodium sulphate

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: We need to identify the electrolyte used to obtain H2S2O8\text{H}_2\text{S}_2\text{O}_8 by electrolysis.

Find: The correct option among the given electrolytes.

Peroxydisulfuric acid is formed during the electrolysis of concentrated sulphuric acid.

The relevant anodic process is:

2HSO4(aq)H2S2O8(aq)+2e2\,\text{HSO}_4^-\,\text{(aq)} \rightarrow \text{H}_2\text{S}_2\text{O}_8\,\text{(aq)} + 2e^-

This requires a high concentration of HSO4\text{HSO}_4^- ions, which is provided by concentrated sulphuric acid.

  • Dilute sodium sulphate solution is not suitable.
  • Dilute sulphuric acid is not suitable because the concentration is low.
  • Acidified dilute sodium sulphate is also not suitable because adequate HSO4\text{HSO}_4^- concentration is not available.

Therefore, the correct option is C.

Option Analysis

Given: Formation of H2S2O8\text{H}_2\text{S}_2\text{O}_8 by electrolysis.

Find: Which electrolyte makes this formation possible.

Electrolyte nature controls the product formed during electrolysis. For peroxydisulfuric acid formation, concentrated sulphuric acid is specifically required.

The formation step is:

2HSO4(aq)H2S2O8(aq)+2e2\,\text{HSO}_4^-\,\text{(aq)} \rightarrow \text{H}_2\text{S}_2\text{O}_8\,\text{(aq)} + 2e^-

Now examine the options:

  1. Dilute solution of sodium sulphate: not suitable because it does not provide the required concentrated bisulphate medium.
  2. Dilute solution of sulphuric acid: not suitable because the concentration is too low.
  3. Concentrated solution of sulphuric acid: suitable because it provides a high concentration of HSO4\text{HSO}_4^- ions.
  4. Acidified dilute solution of sodium sulphate: not suitable because the medium is still dilute and does not adequately support formation of H2S2O8\text{H}_2\text{S}_2\text{O}_8.

Therefore, the electrolyte used is concentrated solution of sulphuric acid, so the correct option is C.

Common mistakes

  • Choosing dilute sulphuric acid because it contains sulphate species. This is wrong because formation of H2S2O8\text{H}_2\text{S}_2\text{O}_8 requires a sufficiently high concentration of HSO4\text{HSO}_4^- ions. Use concentrated sulphuric acid instead.

  • Selecting sodium sulphate solution assuming any sulphate-containing electrolyte will work. This is wrong because the reaction specifically proceeds effectively in a concentrated bisulphate medium, not merely any sulphate solution.

  • Ignoring the role of concentration in electrolysis products. This is wrong because electrolyte concentration can change the anodic product formed. Here, concentrated acid is essential for producing H2S2O8\text{H}_2\text{S}_2\text{O}_8.

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