MCQMediumJEE 2025Isomerism (Structural, Stereoisomerism)

JEE Chemistry 2025 Question with Solution

How many different stereoisomers are possible for the given molecule?

Structure of an organic molecule shown as CH3–CH–CH=CH–CH3 with an OH group attached to the second carbon.
  • A

    33

  • B

    11

  • C

    22

  • D

    44

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: The molecule shown is CH3CH(OH)CH=CHCH3\text{CH}_3-\text{CH}(\text{OH})-\text{CH}=\text{CH}-\text{CH}_3.

Find: The number of different stereoisomers possible.

First count all stereogenic elements in the molecule. The carbon bearing the OH\text{OH} group is a chiral centre because it is attached to four different groups. Also, the C=C\text{C} = \text{C} double bond can show geometrical isomerism because each double-bond carbon has two different substituents.

Thus, there are two independent stereogenic elements in the molecule:

  1. one chiral centre
  2. one geometrical E/ZE/Z double bond

So the total number of stereoisomers is

22=42^2 = 4

There is no internal symmetry that creates a meso form, so all four possibilities are distinct.

Therefore, the total number of different stereoisomers is 44. The correct option is D.

Common mistakes

  • Counting only the chiral centre and ignoring geometrical isomerism at the C=C\text{C} = \text{C} bond is incorrect. The double bond also contributes stereoisomerism because both alkene carbons have different substituents. Include both effects.

  • Using 2n2^n with nn equal only to the number of chiral carbons is wrong here. In this molecule, nn must include the independent alkene stereochemical element as well.

  • Assuming a meso form exists is incorrect. A meso form requires an internal plane of symmetry, which this molecule does not have. Check symmetry before reducing the count.

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