Given: A thin convex lens of glass has refractive index μ and each surface has radius of curvature R. One surface is silvered or polished for complete reflection.
Find: The distance x of the object from the lens so that after refraction, reflection, and refraction again, the final image coincides with the object.
Step 1 — Refraction at the first spherical surface (air to glass):
For a spherical refracting surface,
sn1+s′n2=Rn2−n1
Here n1=1, n2=μ, and if the object is at distance x to the left, then s=−x. So,
−x1+v1μ=Rμ−1
Thus,
v1μ=Rμ−1+x1
and therefore,
v1=Rμ−1+x1μStep 2 — Reflection at the polished spherical face:
For a thin lens, the separation of the two vertices is negligible, so the image distance v1 inside the glass may be treated as the object distance for the mirror.
Using the mirror formula,
sm1+sm′1=R2
with sm=v1, we get
sm′=R2−v111=2v1−Rv1RStep 3 — Refraction back at the first surface (glass to air):
Now the image formed by the mirror serves as a virtual object for refraction back into air. Using the refraction relation with n1=μ and n2=1,
sm′μ+sfinal1=R1−μ
For the final image to coincide with the original object, we require
sfinal=−x
So,
sm′μ+−x1=R1−μStep 4 — Combine and simplify:
Substituting the expressions of v1 and sm′ into the final equation and simplifying gives
x=2(μ−1)RTherefore, the object must be placed at 2(μ−1)R from the lens. Hence, the correct option is D.