Mathematics Question from JEE Main 2025 · 22 January, Shift 1

Let $L_1 : \frac{x - 1}{3} = \frac{y - 1}{-1} = \frac{z + 1}{0}$ and $L_2 : \frac{x - 2}{2} = \frac{y}{0} = \frac{z + 4}{\alpha}$, where $\alpha \in \mathbb{R}$, be two lines which intersect at the point $B$. If $P$ is the foot of the perpendicular from the point $A(1, 1, -1)$ on $L_2$, then the value of $26 \alpha (PB)^2$ is: