MCQMediumJEE Main 2024 · 9 April, Shift 2Equation of Line in 3D

Mathematics Question from JEE Main 2024 · 9 April, Shift 2

Consider the line LL passing through the points (1,2,3)(1, 2, 3) and (2,3,5)(2, 3, 5). The distance of the point (113,113,193)\left(\frac{11}{3}, \frac{11}{3}, \frac{19}{3}\right) from the line LL along the line 3x112=3y111=3z192\frac{3x - 11}{2} = \frac{3y - 11}{1} = \frac{3z - 19}{2} is equal to:

  • A

    33

  • B

    55

  • C

    44

  • D

    66

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