MCQEasyJEE Main 2024 · 6 April, Shift 1Solubility Product

Chemistry Question from JEE Main 2024 · 6 April, Shift 1

For a sparingly soluble salt AB2AB_2, the equilibrium concentrations of A2+A^{2+} ions and B−B^- ions are 1.2×10−4 M1.2 \times 10^{-4} \, \text{M} and 0.24×10−3 M0.24 \times 10^{-3} \, \text{M}, respectively. The solubility product of AB2AB_2 is:

  • A

    0.069×10−120.069 \times 10^{-12}

  • B

    6.91×10−126.91 \times 10^{-12}

  • C

    0.276×10−120.276 \times 10^{-12}

  • D

    27.65×10−1227.65 \times 10^{-12}

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Sign in to see the solution

Practice more Solubility Product questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Start free trialMore on Solubility Product

Related questions