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MCQEasyJEE Main 2025 · 24 January, Shift 1Solubility Product

Chemistry Question from JEE Main 2025 · 24 January, Shift 1

Ksp for Cr(OH)3Cr(OH)_3 is 1.6×10−301.6 \times 10^{-30}. What is the molar solubility of this salt in water?

  • A

    s=1.6×10−30274s = \sqrt[4]{\frac{1.6 \times 10^{-30}}{27}}

  • B

    1.8×10−3027\frac{1.8 \times 10^{-30}}{27}

  • C

    1.8×10−305\sqrt[5]{1.8 \times 10^{-30}}

  • D

    1.6×10−302\sqrt[2]{1.6 \times 10^{-30}}

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