MCQEasyJEE 2024Carbohydrates (Glucose, Fructose, Sucrose…)

JEE Chemistry 2024 Question with Solution

The incorrect statement about glucose is:

  • A

    Glucose is soluble in water because of having an aldehyde functional group

  • B

    Glucose remains in multiple isomeric forms in its aqueous solution

  • C

    Glucose is an aldohexose

  • D

    Glucose is one of the monomer units in sucrose

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given: Four statements about glucose are given.

Find: The incorrect statement.

Check each option using known properties of glucose.

  1. Option A: Glucose is soluble in water because of having an aldehyde functional group.

This is incorrect. Glucose is highly soluble in water mainly because it contains multiple OH-\text{OH} groups. These hydroxyl groups form hydrogen bonds with water. The aldehyde group is not the primary reason for its solubility.

  1. Option B: Glucose remains in multiple isomeric forms in its aqueous solution.

This is correct. In aqueous solution, glucose exists in equilibrium among open-chain and cyclic forms, including α\alpha and β\beta anomers.

  1. Option C: Glucose is an aldohexose.

This is correct. Glucose has six carbon atoms and contains an aldehyde group in its open-chain form, so it is an aldohexose.

  1. Option D: Glucose is one of the monomer units in sucrose.

This is correct. Sucrose is made of glucose and fructose units.

Therefore, the incorrect statement is Option A.

Option-wise Analysis

Given: Statements about the structure and properties of glucose.

Find: Which statement is false.

The key idea is that solubility of carbohydrates in water depends strongly on the number of hydroxyl groups available for hydrogen bonding.

  • Glucose has several OH-\text{OH} groups, so it dissolves readily in water.
  • In aqueous solution, it shows mutarotation because different cyclic and open-chain forms coexist.
  • It is an aldohexose because it is a six-carbon sugar with an aldehyde functionality in the open-chain form.
  • Sucrose is a disaccharide formed from glucose and fructose.

Hence the statement attributing water solubility mainly to the aldehyde group is the incorrect one.

The correct option is A.

Common mistakes

  • Mistake: Assuming the presence of an aldehyde group is the main reason for glucose being soluble in water. Why it is wrong: the dominant factor is hydrogen bonding due to multiple OH-\text{OH} groups. What to do instead: focus on the number of hydroxyl groups in carbohydrate solubility.

  • Mistake: Confusing the term aldohexose with any sugar containing oxygen. Why it is wrong: aldohexose specifically means a six-carbon sugar with an aldehyde group in the open-chain form. What to do instead: identify both the carbon count and the functional group.

  • Mistake: Thinking glucose exists in only one fixed structure in water. Why it is wrong: glucose exists in equilibrium among open-chain and cyclic forms, including α\alpha and β\beta anomers. What to do instead: remember aqueous glucose shows multiple isomeric forms.

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