MCQMediumJEE Main 2024 · 1 February, Shift 1Trigonometric Equations

Mathematics Question from JEE Main 2024 · 1 February, Shift 1

If tanA=1x(x2+x+1)\tan A = \frac{1}{\sqrt{x(x^2 + x + 1)}}, tanB=xx2+x+1\tan B = \frac{\sqrt{x}}{\sqrt{x^2 + x + 1}} and tanC=(x3+x2+x1)1/2\tan C = \left(x^{-3} + x^{-2} + x^{-1}\right)^{1/2}, 0<A,B,C<π/20 < A, B, C < \pi/2, then A+BA + B is equal to:

  • A

    CC

  • B

    πC\pi - C

  • C

    2πC2\pi - C

  • D

    π/2C\pi/2 - C

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Trigonometric Equations questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions