NVAMediumJEE 2024Potassium Dichromate & Permanganate

JEE Chemistry 2024 Question with Solution

Identify correct statements from below: Choose the correct answer from the options given below:

Statements: (A) A. The chromate ion is square planar (B) B. Dichromates are generally prepared from chromates (C) C. The green manganate ion is diamagnetic (D) D. Dark green coloured K2MnO4K_2MnO_4 disproportionates in a neutral or acidic medium to give permanganate (E) E. With increasing oxidation number of transition metal, ionic character of the oxides decreases

Find the number of correct statement(s).

Answer

Correct answer:3

Step-by-step solution

Standard Method

Given: Five statements about chromate, dichromate, manganate and oxides of transition metals are to be checked.

Find: Which statements are correct.

Evaluate each statement one by one:

  1. Statement A: Chromate ion CrO42\text{CrO}_4^{2-} is not square planar. It has tetrahedral geometry. So A is incorrect.

  2. Statement B: Dichromate is prepared from chromate on acidification.

2CrO42+2H+Cr2O72+H2O2\text{CrO}_4^{2-} + 2\text{H}^+ \rightarrow \text{Cr}_2\text{O}_7^{2-} + \text{H}_2\text{O}

So B is correct.

  1. Statement C: Green manganate ion MnO42\text{MnO}_4^{2-} is paramagnetic, not diamagnetic, because it has unpaired electron(s). So C is incorrect.

  2. Statement D: Dark green K2MnO4K_2\text{MnO}_4 disproportionates in neutral or acidic medium to give permanganate.

3K2MnO42KMnO4+MnO2+2KOH3\text{K}_2\text{MnO}_4 \rightarrow 2\text{KMnO}_4 + \text{MnO}_2 + 2\text{KOH}

So D is correct.

  1. Statement E: As oxidation number of transition metal increases, polarising power increases and the oxide shows more covalent character. Hence ionic character decreases. So E is correct.

Therefore, the correct statements are B, D and E only.

Statement-wise Check

Given: The options list five independent statements.

Find: The set of true statements.

  • CrO42\text{CrO}_4^{2-} is tetrahedral, therefore statement A is false.
  • Dichromates are obtained from chromates by acidification, so statement B is true.
  • Green manganate is paramagnetic with one unpaired electron as stated in the solution source, so statement C is false.
  • Statement D is true because manganate disproportionates to permanganate in suitable medium.
  • Statement E is true because higher oxidation state increases covalent character and decreases ionic character of oxides.

Hence the correct option set is B, D, E.

Common mistakes

  • Assuming CrO42\text{CrO}_4^{2-} is square planar because it has four ligands. Four surrounding atoms do not always imply square planar geometry; here the ion is tetrahedral. Always recall the standard geometry of oxoanions.

  • Confusing manganate with permanganate. MnO42\text{MnO}_4^{2-} and MnO4\text{MnO}_4^- have different oxidation states and magnetic behaviour. Check the charge before deciding paramagnetic or diamagnetic nature.

  • Thinking that higher oxidation state means more ionic oxide. In fact, higher charge on the metal cation increases polarising power, so covalent character increases and ionic character decreases. Use Fajan-type reasoning here.

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