MCQMediumJEE 2026Potassium Dichromate & Permanganate

JEE Chemistry 2026 Question with Solution

Consider the following statements about manganate and permanganate ions. Identify the correct statements.

A. The geometry of both manganate and permanganate ions is tetrahedral. B. The oxidation states of Mn in manganate and permanganate are +7+7 and +6+6, respectively. C. Oxidation of Mn(II) salt by peroxodisulphate gives manganate ion as the final product. D. Manganate ion is paramagnetic and permanganate ion is diamagnetic. E. Acidified permanganate ion reduces oxalate, nitrite and iodide ions.

  • A

    A, D and E Only

  • B

    A and D Only

  • C

    A, C and D Only

  • D

    A, B and E Only

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: Statements about manganate and permanganate ions are to be checked.

Find: Which statements are correct.

Step 1: Geometry Both MnO42\mathrm{MnO_4^{2-}} (manganate) and MnO4\mathrm{MnO_4^-} (permanganate) have tetrahedral geometry. So, statement A is correct.

Step 2: Oxidation states In MnO42\mathrm{MnO_4^{2-}}, manganese oxidation state is +6+6. In MnO4\mathrm{MnO_4^-}, manganese oxidation state is +7+7. Therefore, statement B is correct.

Step 3: Oxidation by peroxodisulphate Mn(II) salts oxidize to permanganate, not manganate. So, statement C is false.

Step 4: Magnetic properties Manganate ion with Mn in oxidation state +6+6 has d1d^1 electronic configuration and is paramagnetic. Permanganate ion with Mn in oxidation state +7+7 has d0d^0 electronic configuration and is diamagnetic. So, statement D is correct.

Step 5: Redox properties Acidified permanganate ion is a strong oxidizing agent and oxidizes oxalate, nitrite, and iodide ions. So, statement E is correct.

Thus, the correct statements are A, B and E. Therefore, the correct option is D.

Common mistakes

  • Reversing the oxidation states of manganese in manganate and permanganate. This is wrong because MnO42\mathrm{MnO_4^{2-}} has Mn at +6+6 while MnO4\mathrm{MnO_4^-} has Mn at +7+7. Always calculate oxidation state from the net charge of the ion.

  • Confusing oxidizing and reducing behaviour of acidified permanganate. This is wrong because acidified permanganate oxidizes oxalate, nitrite, and iodide ions; it does not reduce them. Check which species gains electrons and which loses electrons.

  • Assuming paramagnetism or diamagnetism without using d-electron count. This is wrong because magnetic behaviour depends on unpaired electrons: manganate is d1d^1 and paramagnetic, while permanganate is d0d^0 and diamagnetic. First determine oxidation state, then electronic configuration.

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