MCQEasyJEE Main 2024 · 31 January, Shift 1Bohr's Model & Hydrogen Spectrum

Physics Question from JEE Main 2024 · 31 January, Shift 1

If the wavelength of the first member of the Lyman series of hydrogen is λ\lambda, the wavelength of the second member will be:

  • A

    (2732)λ\left(\frac{27}{32}\right)\lambda

  • B

    (3227)λ\left(\frac{32}{27}\right)\lambda

  • C

    (275)λ\left(\frac{27}{5}\right)\lambda

  • D

    (527)λ\left(\frac{5}{27}\right)\lambda

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Bohr's Model & Hydrogen Spectrum questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions