MCQMediumJEE 2024Isomerism (Structural, Stereoisomerism)

JEE Chemistry 2024 Question with Solution

Number of geometrical isomers possible for the given structure is/are:

  • A

    22

  • B

    33

  • C

    44

  • D

    55

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: The solution states that the given structure has two double bonds, and each double bond can show geometrical isomerism.

Find: The number of geometrical isomers possible for the given structure.

For each double bond, two geometrical arrangements are possible: cis or trans.

So the total number of possibilities is

2×2=42 \times 2 = 4

Thus, the total number of geometrical isomers is 44.

Therefore, the correct option is C.

Counting with symmetry note

Given: One part of the solution mentions counting possible configurations using stereochemical choices and then accounting for equivalence.

Find: The number of unique geometrical isomers.

The solution notes an initial count of

23=82^3 = 8

but then states that because of symmetry, some configurations are equivalent.

After removing equivalent arrangements, the number of unique geometrical isomers becomes 44.

Therefore, the number of geometrical isomers possible is 44, so the correct option is C.

Common mistakes

  • Counting only one double bond. This is wrong because the solution indicates that two double bonds can independently show geometrical isomerism. Count the cis/trans possibility for both double bonds.

  • Using the maximum stereoisomer formula without checking equivalence. This is wrong because symmetry can make some configurations identical. Remove equivalent configurations before giving the final count.

  • Treating geometrical isomerism and all stereocenters as the same counting problem. This is wrong because the relevant feature here is the independent cis/trans arrangement of double bonds. Focus on the stereochemical element actually present in the structure.

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